Question
Question: The equations of three circles are \(3 x ^ { 2 } + 3 y ^ { 2 } - 36 x + 81 = 0\) and \(x ^ { 2 } + ...
The equations of three circles are
3x2+3y2−36x+81=0 and x2+y2−16x+81=0The coordinates of the point from which the length of tangents drawn to each of the three circles is equal
A
(433,2)
B
(2, 2)
C
(2,433)
D
None
Answer
None
Explanation
Solution
The required point is the radical centre of the three given circles
Now, S1−S2=0⇒−16y+37=0,
S2−S3=0⇒4x−54=0and S3−S1=0⇒−4x+16y+17=0
Solving these equations, we get
.
Hence the required point is (227,1637)