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Question

Mathematics Question on Conic sections

The equations of the tangents drawn from the origin to the circle x2+y2+2rx+2hy+h2=0,x^2 + y^2 + 2 rx + 2hy + h^2 = 0, are

A

x = 0

B

y-0

C

(h2r2)x2rhy=0(h^2 - r^2)x-2rhy=0

D

(h2r2)x+2rhy=0(h^2 - r^2)x+2rhy=0

Answer

(h2r2)x2rhy=0(h^2 - r^2)x-2rhy=0

Explanation

Solution

Since, tangents are drawn from origin. So, the equation
of tangent be y = m x
\Rightarrow Length of perpendicular from origin = radius
\Rightarrow \hspace25mm \frac{| mr+h |}{\sqrt{m^2+1}}=r
\Rightarrow \hspace15mm m^2r^2+h^2+2mrh=r^2(m^2+1)
\Rightarrow \hspace30mm m=\Bigg|\frac{r^2-h^2}{2rh}\Bigg|, m=\infty
Equationoftangentsarey=r2h22rhx,x=0\therefore Equation of tangents are y=\Bigg|\frac{r^2-h^2}{2rh}\Bigg|x,x=0
Therefore (a) and (c) are the correct answers