Question
Question: The equations of the lines which pass through the origin and are inclined at an angle \(\tan ^ { - ...
The equations of the lines which pass through the origin and are inclined at an angle tan−1m to the line y=mx+c are.
A
x=0,2mx+(m2−1)y=0
B
y=0,2mx+(m2−1)y=0
C
y=0,2mx+(1−m2)y=0
D
None of these
Answer
y=0,2mx+(m2−1)y=0
Explanation
Solution
Angle between both the lines is
tan−1m±tan−1m=tan−11−m22m or tan−10
Therefore equation of lines are y=0 , y=1−m22mx .