Question
Mathematics Question on circle
The equations of the circle which pass through the origin and makes intercepts of lengths 4 and 8 on the x and y-axes respectively are
A
x2+y2±4x±8y=0
B
x2+y2±2x±4y=0
C
x2+y2±8x±16y=0
D
x2+y2±x±y=0
Answer
x2+y2±4x±8y=0
Explanation
Solution
In ΔOAC,OC2=22+42=20
∴ Required equation of circle is
(x±2)2+(y±4)2=20
⇒x2+y2±4x±8y=0