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Question: The equations of sides of a triangle ABC are AB : x + y = 1, BC : 7x – y = 15, AC : 3x – y = 7 the ...

The equations of sides of a triangle ABC are

AB : x + y = 1, BC : 7x – y = 15, AC : 3x – y = 7 the equation of angular bisector containing origin of angle B is

A

2x + y = 3

B

3x + y = 5

C

x + 3y = 7

D

3y –x = –5

Answer

3y –x = –5

Explanation

Solution

Angular bisector of angle B on the side containing origin is

Ž (x+y−1)2=+(7x−y−15)50\frac { ( x + y - 1 ) } { \sqrt { 2 } } = + \frac { ( 7 x - y - 15 ) } { \sqrt { 50 } }

Ž – x + 3y = –5