Question

The equation$ac$ has.

• A. Only one real root $- ac$
• B. At least two real roots
• C. Exactly two real roots
• D. Infinitely many real roots

Answer 1

Answer: (A)

Only one real root $- ac$

Answer 2

$x^{2} - x - 1 = 0$

⇒ $x^{2} - x + 1 = 0$

$x^{2} + x - 1 = 0$......$x^{2} + x + 1 = 0$

Hence, $|x - 2| + |x - 3| = 7$only one real root.

Trick : Check the equation with options then only option (1) satisfies the equation.