Question

The equation to the line which passes through the point of intersection of the two lines 2x + 3y – 1 = 0 and 3x +2y+1= 0, and is normal to the line joining (2, 4), (4, 7) is-

• A. 2y – x – 7 = 0
• B. y – 2x – 6 = 0
• C. 4x + 6y – 1 = 0
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

The slope of the line joining (2, 4) and (4, 7) is $\frac{3}{2}$ and the slope of the line perpendicular

to this is – $\frac{2}{3}$ which is the slope of one of the given lines. The

required line is 2x + 3y – 1 = 0.