Question

The equation to a circle whose centre lies at the point (–2, 1) and which touches the line $3 x - 2 y - 6 = 0$ at (4, 3), is.

• A. $x ^ { 2 } + y ^ { 2 } + 4 x - 2 y - 35 = 0$
• B. $x ^ { 2 } + y ^ { 2 } - 4 x + 2 y + 35 = 0$
• C. $x ^ { 2 } + y ^ { 2 } + 4 x + 2 y + 35 = 0$
• D. None of these

Answer 1

Answer: (A)

$x ^ { 2 } + y ^ { 2 } + 4 x - 2 y - 35 = 0$

Answer 2

Centre (–2, 1), radius $= \sqrt { 36 + 4 } = \sqrt { 40 }$

Hence equation of circle is $x ^ { 2 } + y ^ { 2 } + 4 x - 2 y - 35 = 0$.