Solveeit Logo

Question

Question: The equation \(\sqrt{3}\sin x+\cos x=4\) has A) Infinitely many solutions B) No solutions C) ...

The equation 3sinx+cosx=4\sqrt{3}\sin x+\cos x=4 has
A) Infinitely many solutions
B) No solutions
C) Two solutions
D) Only one solution

Explanation

Solution

For answering this question we should solve the given trigonometric expression 3sinx+cosx=4\sqrt{3}\sin x+\cos x=4 . For doing that we will simplify and transform the given expression into the form of the basic trigonometric formulae sinAcosB+cosAsinB=sin(A+B)\sin A\cos B+\cos A\sin B=\sin \left( A+B \right).

Complete step by step solution:
Now considering from the question we have been asked to simplify the given trigonometric expression 3sinx+cosx=4\sqrt{3}\sin x+\cos x=4 .
Now we will divide the whole expression by 22 on both sides. By doing that we will have 12(3sinx+cosx)=42 32sinx+12cosx=2 \begin{aligned} & \dfrac{1}{2}\left( \sqrt{3}\sin x+\cos x \right)=\dfrac{4}{2} \\\ & \Rightarrow \dfrac{\sqrt{3}}{2}\sin x+\dfrac{1}{2}\cos x=2 \\\ \end{aligned}
Now if we observe carefully then we can say that it is in the form of the basic trigonometric formulae sinAcosB+cosAsinB=sin(A+B)\sin A\cos B+\cos A\sin B=\sin \left( A+B \right) .
Now for further simplifying it we will use the values cos30=32\cos {{30}^{\circ }}=\dfrac{\sqrt{3}}{2} and sin30=12\sin {{30}^{\circ }}=\dfrac{1}{2} from the basic trigonometric concepts.
Now we can write this expression as cos30sinx+sin30cosx=2\Rightarrow \cos {{30}^{\circ }}\sin x+\sin {{30}^{\circ }}\cos x=2 .
Now we will simplify and write it as sin(30+x)=2\Rightarrow \sin \left( {{30}^{\circ }}+x \right)=2 .
From the basic concepts of trigonometry we know that the range of sine trigonometric function is given as 1sinθ1-1\le \sin \theta \le 1 .
Since the value in the right hand side of the trigonometric expression is greater than one. So there does not exist any values for xx .
Hence we can conclude that the number of solutions of the given trigonometric expression 3sinx+cosx=4\sqrt{3}\sin x+\cos x=4 is zero. So we need to mark the option BB as correct.
So, the correct answer is “Option B”.

Note: While answering questions of this type we should be sure with our trigonometric concepts. This question can be answered easily and in a short span of time and very few mistakes are possible in it. We have many other trigonometric formulae similarly for example some of them are sinAcosBcosAsinB=sin(AB)\sin A\cos B-\cos A\sin B=\sin \left( A-B \right) , cosAcosBsinAsinB=cos(A+B)\cos A\cos B-\sin A\sin B=\cos \left( A+B \right) and cosAcosB+sinAsinB=cos(AB)\cos A\cos B+\sin A\sin B=\cos \left( A-B \right) .