Question

The equation of transverse wave is given by y=5sin⁡2π(t0.04−x40), where distance is in cm and time insecond. The wavelength of wave will be

• A. (A) 20 cm
• B. (B) 40 cm
• C. (C) 60 cm
• D. (D) None of these

Answer 1

Answer: (B)

(B) 40 cm

Answer 2

Explanation:
The standard equation of transverse wave isy=asin⁡2π[tT−xλ]where λ is wavelength and a is amplitude.Given, equation isy=5sin⁡2π[t0.04−x40]Comparing Eqs.(i) and (ii), we get⇒xλ=x40λ2=40cm