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Question: The equation of the tangent to the parabola y<sup>2</sup> = 4ax at point (a/t<sup>2</sup>, 2a/t) is...

The equation of the tangent to the parabola y2 = 4ax at point (a/t2, 2a/t) is

A

ty = xt2 + a

B

ty = x + at2

C

y = tx + at2

D

y = tx + (a/t2)

Answer

ty = xt2 + a

Explanation

Solution

eqn of tangent T = 0

y(2at)=4a(x+at22)\left( \frac{2a}{t} \right) = 4a\left( \frac{x + \frac{a}{t^{2}}}{2} \right) ̃ ty = xt2 + a