Question

The equation of the tangent to the parabola
y = (x – 3)2 parallel to the chord joining the points (3, 0) and (4, 1) is-

• A. 2x – 2y + 6 = 0
• B. 2y – 2x + 6 = 0
• C. 4y – 4x + 13 = 0
• D. 4x + 4y = 13

Answer 1

Answer: (C)

4y – 4x + 13 = 0

Answer 2

y*¢* = 2(x –1) = 1 gives the point $\left( \frac{7}{2},\frac{1}{4} \right)$ and the required tangent is y – $\frac{1}{4}$ = 1. $\left( x–\frac{7}{2} \right)$ or 4y – 4x + 13 = 0.