Question

The equation of the tangent to the curve y = t dt at

x = 2 is –

• A. y – 6 log 2 = 7 log 2(x – 2)
• B. y – log 2e^1/3 = (log 2) x
• C. y – 8 log 2e^–1/3 = 5 log 2x
• D. y + 9 log 2 + 2 = (7 log 2)x

Answer 1

Answer: (D)

y + 9 log 2 + 2 = (7 log 2)x

Answer 2

at x = 2, y = $\int_{2}^{4}{\mathcal{l}nt}$dt = t lnt – $t\left| {}_{2}^{4} \right.\$

$\frac{dy}{dx}$ = 2x ln(x²) – lnx