Question
Mathematics Question on Tangents and Normals
The equation of the tangent and normal to the ellipse x2 + 2y2 + 2x - 4y - 14 = 0 at (2, -1) is
A
3x - 4y - 10 = 0, 4x + 3y - 5 = 0
B
4x + 3y - 10 = 0, 3x + 4y - 5 = 0
C
3x - 4y - 5 = 0, 4x - 4y - 10 = 0
D
3x - 4y - 10 = 0, 4x - 3y - 5 = 0
Answer
3x - 4y - 10 = 0, 4x + 3y - 5 = 0
Explanation
Solution
The correct option is (A) : 3x - 4y - 10 = 0, 4x + 3y - 5 = 0.