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Question: The equation of the straight line which passes through the point (–4, 3) such that the portion of th...

The equation of the straight line which passes through the point (–4, 3) such that the portion of the line between the axis is divided internally by the point in the ratio 5 : 3 is

A

9x – 20 y + 96 = 0

B

9x + 20y = 24

C

20x + 9y + 53 = 0

D

None

Answer

9x – 20 y + 96 = 0

Explanation

Solution

n. xx1+myy1=m+n\frac { \mathrm { x } } { \mathrm { x } _ { 1 } } + \mathrm { m } \cdot \frac { \mathrm { y } } { \mathrm { y } _ { 1 } } = \mathrm { m } + \mathrm { n }

3. + 5 = 5 + 3

**–**9x + 20y = 96

9x – 20y + 96 = 0