Question

The equation of the straight line passing through the point (4, 3) and making intercept on the co-ordinates axes whose sum is – 1, is

• A. $\frac { x } { 2 } - \frac { y } { 3 } = - 1$ and $\frac { x } { 2 } + \frac { y } { 1 } = 1$
• B. $\frac { x } { 2 } - \frac { y } { 3 } = - 1$ and $\frac { x } { - 2 } + \frac { y } { 1 } = - 1$
• C. $\frac { x } { 2 } - \frac { y } { 3 } = 1$ and $\frac { x } { 2 } + \frac { y } { 1 } = 1$
• D. $\frac { x } { 2 } + \frac { y } { 3 } = - 1$ and $\frac { x } { - 2 } + \frac { y } { 1 } = - 1$

Answer 1

Answer: (D)

$\frac { x } { 2 } + \frac { y } { 3 } = - 1$ and $\frac { x } { - 2 } + \frac { y } { 1 } = - 1$

Answer 2

Let the equation of line is $\frac { x } { a } + \frac { y } { - 1 - a } = 1$ , which passes through (4, 3). Then $\frac { 4 } { a } + \frac { 3 } { - 1 - a } = 1$ ⇒ $a = \pm 2$

Hence equation is $\frac { x } { 2 } - \frac { y } { 3 } = 1$ and $\frac { x } { - 2 } + \frac { y } { 1 } = 1$ .