Solveeit Logo

Question

Question: The equation of the straight line passing through the point (3, 2) and perpendicular to the line y ...

The equation of the straight line passing through the point

(3, 2) and perpendicular to the line y = x is.

A

xy=5x - y = 5

B

x+y=5x + y = 5

C

x+y=1x + y = 1

D

xy=1x - y = 1

Answer

x+y=5x + y = 5

Explanation

Solution

Let the required equation is y=x+cy = - x + c which is perpendicular to y=xy = x and passes through (3, 2). So 2=3+cc=52 = - 3 + c \Rightarrow c = 5 . Hence required equation is x+y=5x + y = 5.