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Question

Question: The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8) is...

The equation of the plane which bisects the line joining

(2, 3, 4) and (6, 7, 8) is

A

x+y+z15=0x + y + z - 15 = 0

B

xy+z15=0x - y + z - 15 = 0

C

xyz15=0x - y - z - 15 = 0

D

x+y+z+15=0x + y + z + 15 = 0

Answer

x+y+z15=0x + y + z - 15 = 0

Explanation

Solution

Mid-point of (2,3,4) and (6, 7, 8) is (4, 5, 6). This lies on x+y+z15=0x + y + z - 15 = 0 Hence this is the required plane.