The equation of the plane through the pointegral (2, 1, 3) a... | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

The equation of the plane through the point (2, 1, 3) and perpendicular to the vector $4\hat{i}+5\hat{j}+6\hat{k}$ is

A

4x+5y+6z=28

B

2x+y+3z=17

C

4x+5y+6z=33

D

8x+5y+18z=21

E

4x+5y+6z=31

Answer

4x+5y+6z=31

Explanation

Solution

The correct option is (E): 4x+5y+6z=31