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Question

Question: The equation of the plane through the intersection of the planes \(x + 2 y + 3 z - 4 = 0\), \(4 x +...

The equation of the plane through the intersection of the planes x+2y+3z4=0x + 2 y + 3 z - 4 = 0, 4x+3y+2z+1=04 x + 3 y + 2 z + 1 = 0 and passing through the origin will be

A

x+y+z=0x + y + z = 0

B

17x+14y+11z=017 x + 14 y + 11 z = 0

C

7x+4y+z=07 x + 4 y + z = 0

D

17x+14y+z=017 x + 14 y + z = 0

Answer

17x+14y+11z=017 x + 14 y + 11 z = 0

Explanation

Solution

Any plane through the given planes is

(x+2y+3z4)+k(4x+3y+2z+1)=0( x + 2 y + 3 z - 4 ) + k ( 4 x + 3 y + 2 z + 1 ) = 0

It passes through (0, 0, 0)

4+k=0- 4 + k = 0 = k = 4

∴Required plane is (x+2y+3z4)+4(4x+3y+2z+1)=0( x + 2 y + 3 z - 4 ) + 4 ( 4 x + 3 y + 2 z + 1 ) = 0

17x+14y+11z=017 x + 14 y + 11 z = 0