Question
Question: The equation of the plane through the intersection of the planes \(x + 2 y + 3 z - 4 = 0\), \(4 x +...
The equation of the plane through the intersection of the planes x+2y+3z−4=0, 4x+3y+2z+1=0 and passing through the origin will be
A
x+y+z=0
B
17x+14y+11z=0
C
7x+4y+z=0
D
17x+14y+z=0
Answer
17x+14y+11z=0
Explanation
Solution
Any plane through the given planes is
(x+2y+3z−4)+k(4x+3y+2z+1)=0
It passes through (0, 0, 0)
∴ −4+k=0 = k = 4
∴Required plane is (x+2y+3z−4)+4(4x+3y+2z+1)=0
⇒ 17x+14y+11z=0