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Question

Question: The equation of the plane through (1, 2, 3) and parallel to the plane \(2x + 3y - 4z = 0\)is...

The equation of the plane through (1, 2, 3) and parallel to the plane 2x+3y4z=02x + 3y - 4z = 0is

A

2x+3y+4z=42x + 3y + 4z = 4

B

2x+3y+4z+4=02x + 3y + 4z + 4 = 0

C

2x3y+4z+4=02x - 3y + 4z + 4 = 0

D

2x+3y4z+4=02x + 3y - 4z + 4 = 0

Answer

2x+3y4z+4=02x + 3y - 4z + 4 = 0

Explanation

Solution

Plane parallel to the plane 2x+3y4z=02 x + 3 y - 4 z = 0 is

2x+3y4z+k=02 x + 3 y - 4 z + k = 0 .....(i)

Also plane (i) is passing through (1, 2, 3)

\therefore (2)(1)+(3)(2)(4)(3)+k=0k=4( 2 ) ( 1 ) + ( 3 ) ( 2 ) - ( 4 ) ( 3 ) + k = 0 \Rightarrow k = 4

\therefore Required plane is 2x+3y4z+4=02 x + 3 y - 4 z + 4 = 0.