Question
Mathematics Question on Three Dimensional Geometry
The equation of the plane through (1,2,−3) and (2,−2,1) and parallel to X−axis is
A
y−z+1=0
B
y−z−1=0
C
y+z−1=0
D
y+z+1=0
Answer
y+z+1=0
Explanation
Solution
The correct answer is D:y+z+1=0
The points are: (1,2,−3) and (2,−2,1) and parallel to x-axis
Equation of the plane will be
x−1 2−1 1y−2−2−20z+31−(−3)0=0
⇒x−1 1 1y−2−40z+340=0
⇒1[4(y−2)+4(z+3)]=0
⇒4y−8+4z+12=0
⇒4y+4z+4=0
⇒y+z+1=0