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Question

Mathematics Question on Three Dimensional Geometry

The equation of the plane through (1,2,3)(1, 2, -3) and (2,2,1)(2, -2, 1) and parallel to XX-axis is

A

yz+1=0y - z + 1 = 0

B

yz1=0y - z - 1 = 0

C

y+z1=0y + z - 1 = 0

D

y+z+1=0y + z + 1 = 0

Answer

y+z+1=0y + z + 1 = 0

Explanation

Solution

The correct answer is D:y+z+1=0y+z+1=0
The points are: (1,2,3)(1,2,-3) and (2,2,1)(2,-2,1) and parallel to x-axis
Equation of the plane will be
x1y2z+3 21221(3) 100=0\begin{vmatrix} x-1 & y-2 & z+3 \\\ 2-1 & -2-2 & 1-(-3) \\\ 1 & 0 & 0\end{vmatrix}=0
x1y2z+3 144 100=0\Rightarrow \begin{vmatrix} x-1 & y-2 & z+3 \\\ 1 & -4 & 4 \\\ 1 & 0 & 0\end{vmatrix}=0
1[4(y2)+4(z+3)]=0\Rightarrow 1[4(y-2)+4(z+3)]=0
4y8+4z+12=0\Rightarrow 4 y-8+4 z+12=0
4y+4z+4=0\Rightarrow 4 y+4 z+4=0
y+z+1=0\Rightarrow y+z+1=0
X-axis