Question

The equation of the plane passing through the three points are (-2, -2, 2), (1, 1, 1) and (1, -1, 2) is

• A. $x - 3 y - 6 z + 8 = 0$
• B. $x - 3 y + 6 z - 14 = 0$
• C. $x + 3 y + 6 z - 4 = 0$
• D. $x + 3 y - 6 z + 20 = 0$

Answer 1

Answer: (A)

$x - 3 y - 6 z + 8 = 0$

Answer 2

The required plane equation is

$\left| \begin{array} { c c c } x - 1 & y - 1 & z - 1 \\ - 3 & - 3 & 1 \\ 0 & - 2 & 1 \end{array} \right|$= 0;

i.e. $( x - 1 ) ( - 3 + 2 ) + ( y - 1 ) ( 0 + 3 ) + ( z - 1 ) 6 = 0$

i.e. $x - 3 y - 6 z + 8 = 0$