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Question

Mathematics Question on Three Dimensional Geometry

The equation of the plane passing through the points (a,0,0),(0,b,0)(a,0,0),(0,b,0) and (0,0,c)(0,0,c) is

A

ax+by+cz=0ax+by+cz=0

B

ax+by+cz=1ax+by+cz=1

C

xa+yb+zc=1\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1

D

xa+yb+zc=0\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=0

Answer

xa+yb+zc=1\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1

Explanation

Solution

Given points on the plane are (a,0,0),(0,b,0)(a,\,\,0,\,\,0),\,(0,\,b,\,0)
and (0,0,c)(0,\,0,\,c) .
\therefore Length of intercept with x-axis, y-axis and z-axis are a, b and c respectively.
\therefore Equation of the plane is
xa+yb+zc=1\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1