Question

The equation of the plane passing through the origin and perpendicular to the line $x = 2y = 3z$is

• A. $6x + 3y + 2z = 0$
• B. $x + 2y + 3z = 0$
• C. $3x + 2y + z = 0$
• D. None of these

Answer 1

Answer: (A)

$6x + 3y + 2z = 0$

Answer 2

Obviously the line is $\frac { x } { 6 } = \frac { y } { 3 } = \frac { z } { 2 }$ So required plane is $6 ( x - 0 ) + 3 ( y - 0 ) + 2 ( z - 0 ) = 0$.