Question
Question: The equation of the plane passing through the intersection of the planes \(x + 2y + 3z + 4 = 0\) and...
The equation of the plane passing through the intersection of the planes x+2y+3z+4=0 and 4x+3y+2z+1=0 and the origin is
A
3x+2y+z+1=0
B
3x+2y+z=0
C
2x+3y+z=0
D
x+y+z=0
Answer
3x+2y+z=0
Explanation
Solution
Equation of plane passing through the intersection of given planes, is
(x+2y+3z+4)+λ(4x+3y+2z+1)=0 .....(i)
Plane (i) is passing through origin i.e., (0, 0, 0)
∴4+λ=0 ⇒ λ=−4
Put the value of λ in (i),
−15x−10y−5z=0 ⇒ 3x+2y+z=0