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Question: The equation of the plane passing through the intersection of the planes \(x + y + z = 6\) and \(2x ...

The equation of the plane passing through the intersection of the planes x+y+z=6x + y + z = 6 and 2x+3y+4z+5=02x + 3y + 4z + 5 = 0 the point

(1, 1, 1), is

A

20x+23y+26z69=020x + 23y + 26z - 69 = 0

B

20x+23y+26z+69=020x + 23y + 26z + 69 = 0

C

23x+20y+26z69=023x + 20y + 26z - 69 = 0

D

None of these

Answer

20x+23y+26z69=020x + 23y + 26z - 69 = 0

Explanation

Solution

(x+y+z6)+λ(2x+3y+4z+5)=0λ=314( x + y + z - 6 ) + \lambda ( 2 x + 3 y + 4 z + 5 ) = 0 \Rightarrow \lambda = \frac { 3 } { 14 }

20x+23y+26z69=0\Rightarrow 20 x + 23 y + 26 z - 69 = 0 .