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Question

Question: The equation of the plane passing through (2, 3, 4) and parallel to the plane \(5x - 6y + 7z = 3\)...

The equation of the plane passing through (2, 3, 4) and parallel to the plane 5x6y+7z=35x - 6y + 7z = 3

A

5x6y+7z+20=05x - 6y + 7z + 20 = 0

B

5x6y+7z20=05x - 6y + 7z - 20 = 0

C

5x+6y7z+3=0- 5x + 6y - 7z + 3 = 0

D

5x+6y+7z+3=05x + 6y + 7z + 3 = 0

Answer

5x6y+7z20=05x - 6y + 7z - 20 = 0

Explanation

Solution

Equation of the plane passing through (2, 3, 4) is, A(x2)+B(y3)+C(z4)=0A ( x - 2 ) + B ( y - 3 ) + C ( z - 4 ) = 0 …..(i)

Plane (i) is parallel to 5x6y+7z=35 x - 6 y + 7 z = 3

\therefore 5(x2)6(y3)+7(z4)=05 ( x - 2 ) - 6 ( y - 3 ) + 7 ( z - 4 ) = 0

\therefore 5x6y+7z20=05 x - 6 y + 7 z - 20 = 0 is the required plane.