Question
Question: The equation of the plane passing through (2, 3, 4) and parallel to the plane \(5x - 6y + 7z = 3\)...
The equation of the plane passing through (2, 3, 4) and parallel to the plane 5x−6y+7z=3
A
5x−6y+7z+20=0
B
5x−6y+7z−20=0
C
−5x+6y−7z+3=0
D
5x+6y+7z+3=0
Answer
5x−6y+7z−20=0
Explanation
Solution
Equation of the plane passing through (2, 3, 4) is, A(x−2)+B(y−3)+C(z−4)=0 …..(i)
Plane (i) is parallel to 5x−6y+7z=3
∴ 5(x−2)−6(y−3)+7(z−4)=0
∴ 5x−6y+7z−20=0 is the required plane.