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Question

Mathematics Question on Three Dimensional Geometry

The equation of the plane containing the lines 2x5y+z=3,x+y+z=52x - 5y + z = 3, x + y + \, z = 5 and parallel to the plane x+3y+6z=1x + 3 y+ 6 z = 1 is

A

2x+6y+12z=132x + 6y + 12z = 13

B

x+3y+6z=7x + 3y + 6z = - 7

C

x+3y+6z=27x + 3y + 6z = 27

D

2x+6y+12x=132x + 6y + 12x = - 13

Answer

x+3y+6z=27x + 3y + 6z = 27

Explanation

Solution

The correct option is(C): x +3 y +6 z =27.

The given lines are:

  1. 2x - 5y + z = 3
  2. x + y + z = 5

A(xx 0​)+B(yy 0​)+C(zz 0​)=0,

where (A, B, C) is the direction vector of the plane, and (x_0, y_0, z_0) is a point on the plane.

Plugging in the values, we get:

1(x −3)+3(y +2)+6(z −4)=0,

which simplifies to:

x +3 y +6 z =27.

So, the equation of the plane containing the lines 2x - 5y + z = 3 and x + y + z = 5, and parallel to the plane x + 3y + 6z = 1, is

x +3 y +6 z =27.