Question
Mathematics Question on Three Dimensional Geometry
The equation of the plane containing the lines 2x−5y+z=3,x+y+z=5 and parallel to the plane x+3y+6z=1 is
A
2x+6y+12z=13
B
x+3y+6z=−7
C
x+3y+6z=27
D
2x+6y+12x=−13
Answer
x+3y+6z=27
Explanation
Solution
The correct option is(C): x +3 y +6 z =27.
The given lines are:
- 2x - 5y + z = 3
- x + y + z = 5
A(x − x 0)+B(y − y 0)+C(z − z 0)=0,
where (A, B, C) is the direction vector of the plane, and (x_0, y_0, z_0) is a point on the plane.
Plugging in the values, we get:
1(x −3)+3(y +2)+6(z −4)=0,
which simplifies to:
x +3 y +6 z =27.
So, the equation of the plane containing the lines 2x - 5y + z = 3 and x + y + z = 5, and parallel to the plane x + 3y + 6z = 1, is
x +3 y +6 z =27.