Solveeit Logo

Question

Question: The equation of the plane containing the line of intersection of the planes \(2x - y = 0\)and \(y - ...

The equation of the plane containing the line of intersection of the planes 2xy=02x - y = 0and y3z=0y - 3z = 0and perpendicular to the plane 4x+5y3z8=04x + 5y - 3z - 8 = 0is

A

28x17y+9z=028x - 17y + 9z = 0

B

28x+17y+9z=028x + 17y + 9z = 0

C

28x17y+9x=028x - 17y + 9x = 0

D

7x3y+z=07x - 3y + z = 0

Answer

28x17y+9z=028x - 17y + 9z = 0

Explanation

Solution

Equation of plane containing the line of intersection of planes is, (2xy)+λ(y3z)=0( 2 x - y ) + \lambda ( y - 3 z ) = 0 ……(i)

Also, plane (i) is perpendicular to 4x+5y3z8=04 x + 5 y - 3 z - 8 = 0

4(2)+5(λ1)3(3λ)=0\therefore 4 ( 2 ) + 5 ( \lambda - 1 ) - 3 ( - 3 \lambda ) = 0

14λ=3λ=314\Rightarrow 14 \lambda = - 3 \Rightarrow \lambda = - \frac { 3 } { 14 }

Put the value of λ\lambda in (i), we get 28x17y+9z=028 x - 17 y + 9 z = 0 , which is the required plane.