Question
Question: The equation of the plane containing the line <img src="https://cdn.pureessence.tech/canvas_375.png...
The equation of the plane containing the line
is a(x – α) + b(y – β) + c(z – γ) = 0, where al + bm + cn is equal to
A
1
B
–1
C
2
D
0
Answer
0
Explanation
Solution
Since the given straight line lies in the plane, it will be perpendicular to the normal at the given plane.
Since direction cosines of straight line are l, m, n and direction ratios of normal to the plane are
a, b, c, al + bm + cn = 0