Question
Question: The equation of the perpendicular from the point \((\alpha,\beta,\gamma)\) to the plane \(ax + by + ...
The equation of the perpendicular from the point (α,β,γ) to the plane ax+by+cz+d=0is
A
a(x−α)+b(y−β)+c(z−γ)=0
B
ax−α=by−β=cz−γ
C
a(x−α)+b(y−β)+c(z−γ)=abc
D
None of these
Answer
ax−α=by−β=cz−γ
Explanation
Solution
It is a line passing through (α,β,γ) and whose direction cosines are a,b,c