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Question

Question: The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through t...

The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point (6, –3) is

A

y2=12x+6y ^ { 2 } = 12 x + 6

B

x2=12yx ^ { 2 } = 12 y

C

x2=12yx ^ { 2 } = - 12 y

D

y2=12x+6y ^ { 2 } = - 12 x + 6

Answer

x2=12yx ^ { 2 } = - 12 y

Explanation

Solution

Since the axis of parabola is y-axis with its vertex at origin.

∴Equation of parabola x2=4ayx ^ { 2 } = 4 a y . Since it passes through

(6, –3) ; ∴36= –12a ⇒ a=3a = - 3

∴ Equation of parabola is x2=12yx ^ { 2 } = - 12 y