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Question

Question: The equation of the parabola whose vertex is at (2, -1) and focus at (2, -3) is...

The equation of the parabola whose vertex is at (2, -1) and focus at (2, -3) is

A

x2 + 4x – 8y – 12 = 0

B

x2 – 4x + 8y + 12 =0

C

x2 + 8y = 12

D

x2 – 4x + 12 =0

Answer

x2 – 4x + 8y + 12 =0

Explanation

Solution

VS =(22)2+(3+1)2=2\sqrt{(2 - 2)^{2} + ( - 3 + 1)^{2}} = 2. From (x-h)2 = -4a(y-k)

Parabola is

(x – 2)2 = -4.2(y+1)

⇒ (x – 2)2 = -8(y+1)

⇒ x2 + 4 – 4x = -8y – 8

⇒ x2 – 4x + 8y + 12 = 0