Question
Question: The equation of the parabola whose focus is ( 3,-4 ) and directrix 6x- 7y + 5=0 is; \( (a)\;{(...
The equation of the parabola whose focus is ( 3,-4 ) and directrix 6x- 7y + 5=0 is;
(a)(7x+6y)2−570x+750y+2100=0 (b)(7x+6y)2+570x−750y+2100=0 (c)(7x−6y)2−570x+750y+2100=0 (d)(7x−6y)2+570x−750y+2100=0
Solution
Hint: For any point on the line of parabola, the distance to the focus is equal to the perpendicular distance to the directrix.
We know that for any point P(x, y) on the line parabola, the distance to the focus is F(3,-4) is equal to the perpendicular distance to the Directrix line d is,
6x - 7y + 5=0
⇒(62+72)(6x−7y+5)2=(x−3)2+(y+4)2
Now we know that [(a+b+c)2=a2+b2+c2+2(ab+bc+ca)] and hence on applying the same formula we have,
⇒36x2+49y2+25−84xy−70y+60x=85x2+85y2−510x+2125+680y
And hence on doing the simplification, we have
⇒49x2+36y2+84xy−570x+750y+2100=0
And hence it can be written as,
⇒(7x+6y)2−570x+750y+2100=0
So option a is correct answer.
Note: In this type of question first of all we have to find the directrix as well as the Distance to the focus and with the help of that we can find the equation of Parabola.