Question

The equation of the normal to the circle x²+ y² = 9 at the point $\left( \frac { 1 } { \sqrt { 2 } } , \frac { 1 } { \sqrt { 2 } } \right)$ is –

• A. x + y = 0
• B. x – y = $\frac { \sqrt { 2 } } { 3 }$
• C. x – y = 0
• D. None

Answer 1

Answer: (C)

x – y = 0

Answer 2

Normal always passes through centre of circle here centre

(0, 0)

\eqn of normal y – 0= $\frac { 1 / \sqrt { 2 } - 0 } { 1 / \sqrt { 2 } - 0 }$ (x–0)

Ž y = x Ž x–y= 0