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Question

Question: The equation of the locus of all points equidistant from the point (4,2) and the x-axis, is....

The equation of the locus of all points equidistant from the point (4,2) and the x-axis, is.

A

x2+8x+4y20=0x^{2} + 8x + 4y - 20 = 0

B

x28x4y+20=0x^{2} - 8x - 4y + 20 = 0

C

y24y8x+20=0y^{2} - 4y - 8x + 20 = 0

D

None of these

Answer

x28x4y+20=0x^{2} - 8x - 4y + 20 = 0

Explanation

Solution

(x4)2+(y2)2=y2x28x4y+20=0( x - 4 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = y ^ { 2 } \Rightarrow x ^ { 2 } - 8 x - 4 y + 20 = 0.