Solveeit Logo

Question

Question: The equation of the line with slope \(7\) and \(y-\) intercept \(-5\)...

The equation of the line with slope 77 and yy- intercept 5-5

Explanation

Solution

We have to find the equation of line, which is of the form y = mx + b. Here, b denotes the value of y-intercept and m denotes the slope. So, we can substitute the given data in the equation and then we will get the answer.

Complete step by step solution:
The “slope intercept form” of a line is represented by the below equation y=mx+by=mx+b , where mm represents slope and bb represents the yy- intercept. The yy- intercept is the value of yy when we have x=0x=0. Slope is defined as the value that tells the steepness of line and is calculated using the formula m=y2y1x2x1m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}. Thus, it can also be referred to as the ratio of the “vertical change” to the “horizontal change”.
We have been given that:
Slope of the line is 77
The yy- intercept of the line is 5-5
yy- intercept is obtained at x=0x=0.
Therefore, we can write the point that passes through the line as (0,5)\left( 0,-5 \right)
The equation of the line is represented by:
y=mx+by=mx+b …(1)
Substituting the values of slope and yy- intercept in equation (1), we have:
y=7×x+(5)y=7\times x+\left( -5 \right) …(2)
We know that when there is a negative and positive sign and they are multiplied we get a negative number, we have (+)()=\left( + \right)\left( - \right)=-
Therefore, equation (2) can be written as:
y=7x5y=7x-5
Thus, this is the required equation of line when its slope is 77 and yy- intercept is 5-5.

Note: We should keep in mind that yy- intercept is obtained when x=0x=0, if by mistake we take y=0y=0 the answer can come:
y=mx+by=mx+b
y=m×0+b y=b \begin{aligned} & y=m\times 0+b \\\ & y=b \\\ \end{aligned}
Hence the answer obtained in this case is wrong so it should be kept in mind that we use the correct definition of yy- intercept.
Another method to solve this is that yy- intercept is obtained when x=0x=0.
Point obtained is (0,5)\left( 0,-5 \right).
The equation of the line is obtained as:
yy1=m(xx1) y(5)=7(x0) y+5=7x \begin{aligned} & y-{{y}_{1}}=m\left( x-{{x}_{1}} \right) \\\ & y-\left( -5 \right)=7\left( x-0 \right) \\\ & y+5=7x \\\ \end{aligned}