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Question

Question: The equation of the line perpendicular to line \(a x + b y + c = 0\) and passing through \(( a , b )...

The equation of the line perpendicular to line ax+by+c=0a x + b y + c = 0 and passing through (a,b)( a , b )is equal to.

A

bxay=0b x - a y = 0

B

bx+ay2ab=0b x + a y - 2 a b = 0

C

bx+ay=0b x + a y = 0

D

None of these

Answer

bxay=0b x - a y = 0

Explanation

Solution

Equation of line perpendicular to ax+by+c=0a x + b y + c = 0 is bxay+λ=0b x - a y + \lambda = 0 .....(i)

It passes through (a, b)

So, from equation (i), abab+λ=0λ=0a b - a b + \lambda = 0 \Rightarrow \lambda = 0

So equation of line is bxay=0b x - a y = 0.