Question

The equation of the line perpendicular to 2x – 3y + 5 = 0 and making an intercept 3 with positive Y-axis is

• A. 3x + 2y – 6 = 0
• B. 3x + 2y – 12 = 0
• C. 3x + 2y – 7 = 0
• D. 3x + 2y + 6 = 0

Answer 1

Answer: (A)

3x + 2y – 6 = 0

Answer 2

Given equation of line is 2x-3y+5=0;
The slope of the given line is 2/3.
Therefore, the slope of the perpendicular to the given line is m= -$\frac {3}{2}$.
Also, line intercept y-axis = 3, i.e., c = 3.
We know That
y = mx+c
y = -$\frac {3}{2}$x + 3
2y = -3x + 6
3x+2y-6=0
Therefore, the correct option is (A) 3x+2y-6=0