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Question: The equation of the line passing through the points ( 3, 2, 4) and (4, 5, 2) is...

The equation of the line passing through the points ( 3, 2, 4) and (4, 5, 2) is

A

x+31=y+23=z+4−2\frac { x + 3 } { 1 } = \frac { y + 2 } { 3 } = \frac { z + 4 } { - 2 }

B

x−31=y−23=z−4−2\frac { x - 3 } { 1 } = \frac { y - 2 } { 3 } = \frac { z - 4 } { - 2 }

C

x+37=y+27=z+46\frac { x + 3 } { 7 } = \frac { y + 2 } { 7 } = \frac { z + 4 } { 6 }

D

x−37=y−27=z−46\frac { x - 3 } { 7 } = \frac { y - 2 } { 7 } = \frac { z - 4 } { 6 }

Answer

x−31=y−23=z−4−2\frac { x - 3 } { 1 } = \frac { y - 2 } { 3 } = \frac { z - 4 } { - 2 }

Explanation

Solution

Required line is x−34−3=y−25−2=z−42−4\frac { x - 3 } { 4 - 3 } = \frac { y - 2 } { 5 - 2 } = \frac { z - 4 } { 2 - 4 }

i.e., x−31=y−23=z−4−2\frac { x - 3 } { 1 } = \frac { y - 2 } { 3 } = \frac { z - 4 } { - 2 }.