Question
Question: The equation of the line passing through the point (1, 2) and perpendicular to the line \(x + y + 1 ...
The equation of the line passing through the point (1, 2) and perpendicular to the line x+y+1=0 is.
A
y−x+1=0
B
y−x−1=0
C
y−x+2=0
D
y−x−2=0
Answer
y−x−1=0
Explanation
Solution
The line perpendicular to the line x+y+1=0 is y−x+λ=0. Also, it passes through the point (1, 2);
∴ λ=−1 . Hence, required line is y−x−1=0.