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Question

Question: The equation of the line passing through the point (1, 2) and perpendicular to the line \(x + y + 1 ...

The equation of the line passing through the point (1, 2) and perpendicular to the line x+y+1=0x + y + 1 = 0 is.

A

yx+1=0y - x + 1 = 0

B

yx1=0y - x - 1 = 0

C

yx+2=0y - x + 2 = 0

D

yx2=0y - x - 2 = 0

Answer

yx1=0y - x - 1 = 0

Explanation

Solution

The line perpendicular to the line x+y+1=0x + y + 1 = 0 is yx+λ=0y - x + \lambda = 0. Also, it passes through the point (1, 2);

\therefore λ=1\lambda = - 1 . Hence, required line is yx1=0y - x - 1 = 0.