Question

The equation of the line passes through (a, b) and parallel to the line $\frac { x } { a } + \frac { y } { b } = 1$, is

• A. $\frac { x } { a } + \frac { y } { b } = 3$
• B. $\frac { x } { a } + \frac { y } { b } = 2$
• C. $\frac { x } { a } + \frac { y } { b } = 0$
• D. $\frac { x } { a } + \frac { y } { b } + 2 = 0$

Answer 1

Answer: (B)

$\frac { x } { a } + \frac { y } { b } = 2$

Answer 2

The equation of parallel line to given line is $\frac { x } { a } + \frac { y } { b } = \lambda$.

This line passes through point (a, b).

$\therefore$ $\frac { a } { a } + \frac { b } { b } = \lambda$ ⇒ $\lambda = 2$

Hence, required line is $\frac { x } { a } + \frac { y } { b } = 2$.