Question
Question: The equation of the line parallel to the line \(2 x - 3 y = 1\) and passing through the middle point...
The equation of the line parallel to the line 2x−3y=1 and passing through the middle point of the line segment joining the points (1, 3) and (1, – 7), is.
A
2x−3y+8=0
B
2x−3y=8
C
2x−3y+4=0
D
2x−3y=4
Answer
2x−3y=8
Explanation
Solution
Mid point ≡(21+1,23−7)=(1,−2)
Therefore required line is 2x−3y=k⇒2x−3y=8.