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Question: The equation of the line parallel to the line \(2 x - 3 y = 1\) and passing through the middle point...

The equation of the line parallel to the line 2x3y=12 x - 3 y = 1 and passing through the middle point of the line segment joining the points (1, 3) and (1, – 7), is.

A

2x3y+8=02 x - 3 y + 8 = 0

B

2x3y=82 x - 3 y = 8

C

2x3y+4=02 x - 3 y + 4 = 0

D

2x3y=42 x - 3 y = 4

Answer

2x3y=82 x - 3 y = 8

Explanation

Solution

Mid point (1+12,372)=(1,2)\equiv \left( \frac { 1 + 1 } { 2 } , \frac { 3 - 7 } { 2 } \right) = ( 1 , - 2 )

Therefore required line is 2x3y=k2x3y=82 x - 3 y = k \Rightarrow 2 x - 3 y = 8.