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Question

Mathematics Question on Three Dimensional Geometry

The equation of the line joining the points (3,4,11)(-3,4,11) and (1,2,7)(1,-2,7) is

A

x+32=y43=z114\frac{x+3}{2}=\frac{y-4}{3}=\frac{z-11}{4}

B

x+32=y43=z112\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}

C

x+32=y+43=z+114\frac{x+3}{-2}=\frac{y+4}{3}=\frac{z+11}{4}

D

x+32=y+43=z+112\frac{x+3}{2}=\frac{y+4}{-3}=\frac{z+11}{2}

Answer

x+32=y43=z112\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}

Explanation

Solution

A(3,4,11)B(1,2,7)A (-3,4,11) B (1,-2,7) Dr's of ABAB (a,b,c)=1(3),(2,4)7,11( a , b , c )=1-(-3),(-2,-4) 7,-11 4,6,44,-6,-4 =2,3,2=-2,3,2