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Question

Mathematics Question on Three Dimensional Geometry

The equation of the line joining the points (-3, 4, 11) and (1, -2, 7) is

A

x+32=y−43=z−114\frac{x+3}{2}=\frac{y-4}{3}=\frac{z-11}{4}

B

x+3−2=y−43=z−112\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}

C

x+3−2=y+43=z+114\frac{x+3}{-2}=\frac{y+4}{3}=\frac{z+11}{4}

D

x+32=y+4−3=z+112\frac{x+3}{2}=\frac{y+4}{-3}=\frac{z+11}{2}

Answer

x+3−2=y−43=z−112\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}

Explanation

Solution

The correct answer is (B) : x+3−2=y−43=z−112\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}.