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Question: The equation of the hyperbola whose directrix is x + 2y = 1, focus (2, 1) and eccentricity 2 will be...

The equation of the hyperbola whose directrix is x + 2y = 1, focus (2, 1) and eccentricity 2 will be

A

x2 – 16xy – 11y2 – 12x + 6y + 21 = 0

B

3x2 + 16xy + 15y2 – 4x – 14y – 1 = 0

C

x2 + 16xy + 11y2 – 12x – 6y + 21 = 0

D

None of these

Answer

x2 – 16xy – 11y2 – 12x + 6y + 21 = 0

Explanation

Solution

Here coefficient of x2 is +ve and that of y2 is –ve i.e., a hyperbola.