Question
Question: The equation of the hyperbola whose directrix is x + 2y = 1, focus (2, 1) and eccentricity 2 will be...
The equation of the hyperbola whose directrix is x + 2y = 1, focus (2, 1) and eccentricity 2 will be
A
x2 – 16xy – 11y2 – 12x + 6y + 21 = 0
B
3x2 + 16xy + 15y2 – 4x – 14y – 1 = 0
C
x2 + 16xy + 11y2 – 12x – 6y + 21 = 0
D
None of these
Answer
x2 – 16xy – 11y2 – 12x + 6y + 21 = 0
Explanation
Solution
Here coefficient of x2 is +ve and that of y2 is –ve i.e., a hyperbola.