Question
Question: The equation of the hyperbola whose conjugate axis is 5 and the distance between the foci is 13, is...
The equation of the hyperbola whose conjugate axis is 5 and the distance between the foci is 13, is
A
25x2 – 144y2 = 900
B
144x2 – 25y2 = 900
C
144x2 + 25y2 = 900
D
25x2 + 144y2 = 900
Answer
25x2 – 144y2 = 900
Explanation
Solution
Let the equation a2x2 – b2y2 = 1
Given 2b = 5 Ž b = 5/2 and 2ae = 13
Ž ae = 13/2
Now b2 = a2(e2 – 1)
Ž b2 = a2e2 – a2
425 = 4169 – a2 Ž a2 = 4144
\ equation 4144x2 – 425y2 = 1
25x2 – 144y2 = 900