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Question

Question: The equation of the hyperbola whose conjugate axis is 5 and the distance between the foci is 13, is...

The equation of the hyperbola whose conjugate axis is 5 and the distance between the foci is 13, is

A

25x2 – 144y2 = 900

B

144x2 – 25y2 = 900

C

144x2 + 25y2 = 900

D

25x2 + 144y2 = 900

Answer

25x2 – 144y2 = 900

Explanation

Solution

Let the equation x2a2\frac{x^{2}}{a^{2}}y2b2\frac{y^{2}}{b^{2}} = 1

Given 2b = 5 Ž b = 5/2 and 2ae = 13

Ž ae = 13/2

Now b2 = a2(e2 – 1)

Ž b2 = a2e2 – a2

254\frac{25}{4} = 1694\frac{169}{4} – a2 Ž a2 = 1444\frac{144}{4}

\ equation x21444\frac{x^{2}}{\frac{144}{4}}y2254\frac{y^{2}}{\frac{25}{4}} = 1

25x2 – 144y2 = 900