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Question

Question: The equation of the directrix of parabola \(5 y ^ { 2 } = 4 x\) is...

The equation of the directrix of parabola 5y2=4x5 y ^ { 2 } = 4 x is

A

4x1=04 x - 1 = 0

B

4x+1=04 x + 1 = 0

C

5x+1=05 x + 1 = 0

D

5x1=05 x - 1 = 0

Answer

5x+1=05 x + 1 = 0

Explanation

Solution

The given parabola is y2=45xy ^ { 2 } = \frac { 4 } { 5 } x . Here a=15a = \frac { 1 } { 5 } .

Directrix is 5x+1=05 x + 1 = 0