Question
Question: The equation of the conic with focus at (1, – 1), directrix along \(x - y + 1 = 0\) and with eccentr...
The equation of the conic with focus at (1, – 1), directrix along x−y+1=0 and with eccentricity 2is
A
x2−y2=1
B
xy=1
C
2xy−4x+4y+1=0
D
2xy+4x−4y−1=0
Answer
2xy−4x+4y+1=0
Explanation
Solution
Here, focus (S) = (1, –1), eccentricity (5)=2
From definition , SP=ePM
(x−1)2+(y+1)2=12+122.(x−y+1)⇒ (x−1)2+(y+1)2 =
(x−y+1)2 ⇒ 2xy−4x+4y+1=0, which is the required equation of conic (Rectangular hyperbola)
